应用题-二叉树专题-左节点之和
```python
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def sumOfLeftLeaves(self, root: Optional[TreeNode]) -> int:
self.left_sum = 0
def cal_left_sum( r ):
if not r: return
# 站在r上 r的左节点是叶子节点
if r.left and not r.left.left and not r.left .right: self.left_sum += r.left.val
cal_left_sum( r.left )
cal_left_sum( r.right )
cal_left_sum( root )
return self.left_sum
```
```python
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def sumOfLeftLeaves(self, root: Optional[TreeNode]) -> int:
if not root: return 0
if not root.left and not root.right: return 0
l = self.sumOfLeftLeaves( root.left )
if root.left and not root.left.left and not root.left.right: l += root.left.val
r = self.sumOfLeftLeaves( root.right )
return l + r
```